6x^2-28x-20=0

Solution for 6x^2-28x-20=0 equation:

6x^2-28x-20=0

a = 6; b = -28; c = -20;
Δ = b2-4ac
Δ = -282-4·6·(-20)
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{79}}{2*6}=\frac{28-4\sqrt{79}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{79}}{2*6}=\frac{28+4\sqrt{79}}{12}
$